TR Missile & Smart Munition Programs

[Huelague]

That looks like Pi to me, my calculations show 1.26 k m² which is still big enough for a 2000 lb drop.

A = π • r²
r = 1 km² (radius of destruction, as estimated)
π ~3,142
A = 3,142 • 1 (km²)
A = 3,142 km² (destruction zone)
Still.

 

[Radko]

As it is, it quite literally cannot.

Idk, tell that to the ones in Roketsan. That's what I heard in IDEF day 2